10n^2-32n+22=0

Solution for 10n^2-32n+22=0 equation:

10n^2-32n+22=0

a = 10; b = -32; c = +22;
Δ = b2-4ac
Δ = -322-4·10·22
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-12}{2*10}=\frac{20}{20}
=1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+12}{2*10}=\frac{44}{20}
=2+1/5
$